C++ program for Palindrome Number using While Loop

Before going to the program first let us understand what is a Palindrome Number?

Palindrome Number:

                                  It is a number which remains same even when the number is reversed.

For example,

                    Numbers like 0,1,2,11,55,131,262,464,453354 are called as Palindrome Numbers.

Program code to find whether a Number is Palindrome or Not:

#include<iostream.h>
#include<conio.h>
void main()
{ int n,a,r,s=0; clrscr(); cout<<"n Enter The Number:"; cin>>n; a=n; while(n>0) { r=n%10; s=s*10+r; n=n/10; } /* CHECKING IF THE NUMBER ENTERED AND THE REVERSE NUMBER IS EQUAL OR NOT */ if(a==s) { cout<<a<<" is a Palindrome Number"; } else { cout<<a<<" is not a Palindrome Number"; } getch();
}

Related: C program for Palindrome Number using while Loop

Working:

• First the computer reads the number to find the reverse of the number.
• Then using while loop the reverse number is calculated.
• Then finally the reverse number is compared with the entered number and if they are equal then it is printed as “(Given number) is a palindrome number ” else it is printed as “(Given number) is not a palindrome number “.

Step by Step working of the above Program Code:

Let us assume that the number entered by the user is 121.

1. It assigns the value of s=0,n=121.
2. Then it assigns the value of a=n (a=121).
3. Then the loop continues till the condition of the while loop is true.

3.1.    n>0  (121>0)  while loop condition is true

r=n%10         (r=121%10)       So  r=1

s=s*10+r     (s=0*10+1)       So  s=1

n=n/10          (n=121/10)      So  n=12

3.2.    n>0  (12>0)  while loop condition is true

r=n%10         (r=12%10)       So  r=2

s=s*10+r     (s=1*10+2)       So  s=12

n=n/10          (n=12/10)        So  n=1

3.3.    n>0  (1>0)  while loop condition is true

r=n%10         (r=1%10)        So  r=1

s=s*10+r     (s=12*10+1)      So  s=121

n=n/10          (n=1/10)         So  n=0

3.4.    n>0  (0>0)  while loop condition is false

It comes out of the while loop and checks whether the number is palindrome or not.

4. a==s  (121==121)   if condition is true

It prints 121 is a palindrome number.

5. Thus the program execution is completed.

In the above working, step:4 if condition can also be false for some other number like ’12’.

Then for that it goes to the else part and prints 12 is not a palindrome number.

Output:

TO DOWNLOAD THE PROGRAM CODES : CLICK HERE