Before going to the program for Cosine Series first let us understand what is a Cosine Series?
Cosine Series:
Cosine Series is a series which is used to find the value of Cos(x).
where, x is the angle in degree which is converted to Radian.
The formula used to express the Cos(x) as Cosine Series is

Expanding the above notation, the formula of Cosine Series is
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For example,
Let the value of x be 30.

So, Radian value for 30 degree is 0.52359.

So, the value of Cos(30) is 0.8660.
Program code for Cosine Series in C:
#include<iostream.h>
#include<iomanip.h>
#include<conio.h> void main()
{ int i, n; float x, sum=1, t=1; clrscr(); cout<<" Enter the value for x : "; cin>>x; cout<<" Enter the value for n : "; cin>>n; x=x*3.14159/180; /* Loop to calculate the value of Cosine */ for(i=1;i<=n;i++) { t=t*(-1)*x*x/(2*i*(2*i-1)); sum=sum+t; } cout<<" The value of Cos("<<x<<") = "<<setprecision(4)<<sum; getch();
}
Note: setprecision(4) is used to set the floating point number upto 4 decimal points.
iomanip.h is a header file which contains the setprecision() function.
Related: C++ program for Sine Series
Working:
- First the computer reads the value of ‘x’ and ‘n’ from the user.
- Then ‘x’ is converted to radian value.
- Then using for loop the value of Cos(x) is calculate.
- Finally the value of Cos(x) is printed.
Related: C++ program for Exponential Series
Step by Step working of the above Program Code:
Let us assume that the user enters the value of ‘x’ as 45 and ‘n’ as 3.
- Converting ‘x’ to radian value
x = x * 3.14159 / 180 (x = 45 * 3.14159 / 180) So, x=0.78539
- It assigns t=1 and sum=1
- It assigns the value of i=1 and the loop continues till the condition of the for loop is true.
3.1. i<=n (1<=3) for loop condition is true
t = (1 * (-1) * 0.78539 * 0.78539)/(2 * 1 * (2 * 1 – 1))
So, t = – 0.30841
sum = 1 + (- 0.30841)
So, sum=0.69159
i++
So, i=2
3.2. i<=n (2<=3) for loop condition is true
t = (- 0.30841 * (-1) * 0.78539 * 0.78539)/(2 * 2 * (2 * 2 – 1))
So, t = 0.01585
sum = 0.69159 + 0.01585
So, sum=0.70744
i++
So, i=3
3.3. i<=n (3<=3) for loop condition is true
t = (0.01585 * (-1) * 0.78539 * 0.78539)/(2 * 3 * (2 * 3 – 1))
So, t = – 0.000325
sum = 0.70744 + (- 0.000325)
So, sum=0.70711
i++
So, i=4
3.4. i<=n (4<=3) for loop condition is false
It comes out of the for loop.
- Finally it prints The value of Cos(0.78539) = 0.7071
- Thus program execution is completed.
Output:




